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In the morning class, the mean on the first exam was 78 with a standard deviation of 2.3 for
the 57 students in the class. In the afternoon class, the mean was 81 with a standard deviation
of 5.7 for the 37 students in the class. Determine the 90% confidence interval for the
difference in the means of the two groups

 __ 

Using Minitab Output:

Two-Sample T-Test and CI

Sample   N   Mean  StDev  SE Mean
1       57  78.00   2.30     0.30
2       37  81.00   5.70     0.94


Difference = μ (1) - μ (2)
Estimate for difference:  -3.000
90% CI for difference:  (-4.656, -1.344)
T-Test of difference = 0 (vs ≠): T-Value = -3.04  P-Value = 0.004  DF = 43

 

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