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Recent research indicated that about 30​% of children in a certain country are deficient in vitamin D. A company that sells vitamin D supplements tests 370 elementary school children in one area of the country. Use a Normal approximation to find the probability that no more than 99 of them have vitamin D deficiency.

Calculate the standard deviation and the mean of the distribution using the n*p and the n*p*q formulas. 

mean = 0.3 * 370 =  111 and the standard deviation is  = sqrt(0.3 * 0.7 * 3670)  =  8.815

Then apply the standard normal distribution function, =NORM.DIST(99,B2,B3,TRUE) = 

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