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Assume that you have a sample of n1 = 4, with the sample mean X_bar1 = 48, and a sample standard deviation of S1 = 4

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Assume that you have a sample of n1 = 4, with the sample mean X_bar1 = 48, and a sample standard deviation of S1 = 4, and you have an independent sample of n2 = 6 from another population with a sample mean of X_bar2 = 39 and the sample standard deviation S2 = 3. Assuming the population variances are equal, at the 0.01 level of significance, is there evidence that u1 > u2?

Determine the hypotheses.

Find the test statistic

Find the p-value

Make the correct decision about the null hypothesis.

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tutor

tutor Added an answer on Jun 04,2019

Assuming equal variance means the standard deviations have to be pooled.

s^2 = ((n1-1)*s1^2 + (n2-1)*s2^2)/(n1 + n2 - 2) = 11.625

s^2 = 11.625

we test the claim that the mean of the population for the first sample is greater.

t = (48 - 39)/s*(1/n1 + 1/n2)

t = (48 - 39)/3.41*sqrt(1/4 + 1/6) = 17.72

Reject the null hypothesos

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Assume that you have a sample of n1 = 4, with the sample mean X_bar1 = 48, and a sample standard deviation of S1 = 4

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