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Probability question from Poisson distribution. 

A life insurance salesman sells on the average 3 life insurance policies per week. Calculate the probability that in a given week he will sell  Some policies, 2 or more policies but less than 5 policies,  Assuming that there are 5 working days per week, what is the probability that in a given day he will sell one policy? Solve the question using Excel. 

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The Distribution follows a Poisson Distribution with a mean of 3.

a Some policies      
  Average = 3    
  some policies = p(x>=1)    
  p(X>=1)   0.9502    
b 2 or more policies but less than 5 policies
  P(x>=2 and X < 5>      
  p(X>=2) = 1-p(X<=1)   0.1991483  
  P(x<5 p(x<=4)>   0.8152632  
  P(x>=2 and X<5>   0.6161  
  Average Policies Per day =  0.60  
  Probability of Exactly 3 policies in 1 day 0.3293  
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